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NCERT SOLUTION
CLASS XTH: REAL NUMBERS
Q1: Use Euclid’s division algorithm to find the
HCF of
(I)
135 and 225
(ii) 196 and 38220 (iii) 867, 255
Solution
To start the solution, first, we
write the Euclid division lemma
Let a, b, q, and r be integers
such that a = bq + r.
Where 0 < a, a is the dividend, b is the quotient, and r is the
remainder. if the remainder r = 0, then HCF = b.
For the HCF of 135 and 225
225 = 135x1 + 90
135 = 90x1 + 45
90 = 45x2 + 0. Here, the remainder is 0; hence, we can consider 45 as an HCF
HCF = 45
(ii) 38220 is greater than 196, so
divide 38220 by 196 and note down the quotient and remainder, a = 38220, b
= 196, r = 0
We can write by the Euclid division
lemma
38220 = 196x195 + 0
Hence HCF = 196
(iii) 867 and 255
In this question, 867 is greater than 255, so we divide 855 by 255 and note the remainder and the quotient
867 =
255x3+102
Here, remainder is not zero
Again 255 = 102x2 + 51.
102 = 2x51 + 0
Here, HCF is 251.
Chapter 2 Polynomials
Polynomials are expressions containing more than one term.
Types
Monomial: The expression containing only one term, ex. P(x) = 2x
Binomial: The expression containing two terms
Ex: 2x+3y has two terms
Trinomial: An expression containing three terms
P(x) = x+2y+3z
Zeros of the polynomial
The value of the variable that makes the polynomial zero is said to be za ero of the polynomial
ex: (x+2)
If we put x+2 = 0 or x = -2, it will be zero
to get such a type of answer, we write P(x) =0
and solve for x, or try to find the value of x
In Figure 1, the curve does not touch the x-axis, so it has no real root.In figure (ii), we can see the curve crosses the x-axis at time, so it has one zero
In 3, the curve touches the x-axis only once, so it has one zero
In fig. V, the graph touches the axis 3 times, so the number of solutions = =3
In Figure6, the curve touches or crosses the x-axis 6 times, so the number of solutions = 6
Exercise 2.1
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