NCERT-CLASSS-10-VOLUME-AND-SURFACE-AREA-1
SURFACE AREAS AND VOLUMES
EXERCISE 12.1
If we join two cubes,
then it will form a cuboid.
Then the length
of the cuboid = 4 cm + 4cm = 8cm.
Height of the
cuboid = 4cm
Width = 4cm
Therefore, the
total surface area of the cuboid = 2(lb + b*h + h*l)
=2*(8*4
+4*4+4*8)
= 2*(32 + 16 + 32)
=
160 cm2
Diameter of
hemisphere = 2r = 14cm
Radius = 14/2 =
7cm
Total height of
the container = 13cm
Height of the cylindrical
part = 13-7 cm = 6cm
Inner surface
area total = curved surface area of hemisphere curved surface area of cylinder
= 2∏r + 2∏rh = 2∏r(r + h)
= 2*(22/7)*7(7+6)
= 2 * 22 * 13 = 2 * 286
= 572 cm2
= 2*(22/7)*3.5 * (3.5 +12.5)
= 2*11*16
= 356 cm2
= 2∏r2+ 6a2 - ∏(r)2
= 6a + ∏(r)²
Where ‘a is the
side of the cube.
= 6 * 7 * 7 +
(22/7)*3.5*3.5
= 294 + 38.5
= 277 cm2
5. A hemispherical depression is cut out from one face of a cubical wooden block, such
that the diameter l of the hemisphere is equal to the edge of the cube. Determine the
surface area of the remaining solid.
Question 8: From a solid cylinder, whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm².











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